char a[5]={"1234"};
cout<<a<<endl;
我知道第二句的a是字符串的首地址，被<<重载在这里输出a所指向的内容，即1234。 问题是如果我想知道a的值，就是那个0x...的16进制表示的数怎么办啊？怎么才能得到？
cout<<a<<endl;
我知道第二句的a是字符串的首地址，被<<重载在这里输出a所指向的内容，即1234。 问题是如果我想知道a的值，就是那个0x...的16进制表示的数怎么办啊？怎么才能得到？
c++吧 关注：609,477贴子：2,109,695
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@暗darkt
ISO/IEC C11 N1570
6.3.2 Other operands
6.3.2.1 Lvalues, arrays, and function designators
3 Except when it is the operand of the sizeof operator, the _Alignof operator, or the unary & operator, or is a string literal used to initialize an array, an expression that has type ‘‘array of type’’ is converted to an expression with type ‘‘pointer to type’’ that points to the initial element of the array object and is not an lvalue. If the array object has register storage class, the behavior is undefined.
ISO/IEC C11 N1570
6.3.2 Other operands
6.3.2.1 Lvalues, arrays, and function designators
3 Except when it is the operand of the sizeof operator, the _Alignof operator, or the unary & operator, or is a string literal used to initialize an array, an expression that has type ‘‘array of type’’ is converted to an expression with type ‘‘pointer to type’’ that points to the initial element of the array object and is not an lvalue. If the array object has register storage class, the behavior is undefined.
