有点费劲儿:引理:arccosx=pi/2-arcsinx,然后括号里面就等于arcsin(1/根10)+pi/2-arcsin(-2/根10)=arcsin(1/根10)+arcsin(2/根10)+pi/2。引理:arcsinx+arcsiny=arcsin(x(1-y^2)^0.5+y(1-x^2)^0.5)(x,y同号时须满足x^2+y^2<=1)可知上面两个数满足条件,最终括号里面算出来是pi/2+arcsin(7/根50),那么sin(整体)=cos(arcsin(7/根50))=根2/10