#count ht number.py
def number(s):
#please input the string ,this function will out the number of lettter')
a=0
b=0
c=(len(s)-1)
for i in range(c):
char1=s[i]#notice the (i-1) probably is -1 !
for n in range((i-1)):
while char1!=s[n] and b<=c:
if char==s[b]:
a=a+1
b=n+1
print(char+'has '+str(a))
print()
print()

# in fact ,the idea is right,but I do not know why the format is wrong,maybe i need
def count(x):
c=len(x)
char=[]
for n in range((c-1)):
z=x[n]
char=char.append(z)
char1=char
for n in range((c-1)):
a=char1.count(char1[n])
b=char1.index(char1[n])
if b==n:
print(str(a)+': '+str(n))
else:
print()