求助，请问两个DS18B20如何与单片机实现使用

谢谢了

#include<reg52.h>
#include<stdio.h>
#define uchar unsigned char
#define uint unsigned int
sbit ds=P1^3;
sbit rs=P2^4;
sbit rw=P2^5;
sbit en=P2^6;
uchar code tq1[]={0x28,0xee,0x5c,0xec,0x02,0x00,0x00,0x84};
uchar code tq2[]={0x28,0xee,0x5c,0xec,0x02,0x00,0x00,0x85};
uchar num=1;
//bit Init_DS18B20(void);
//unsigned char ReadOneChar(void);
//void WriteOneChar(unsigned char dat);
//unsigned int ReadTemperature(void);
//void DelayUs2x(unsigned char t);
//void DelayMs(unsigned char t);
//void write_com(uchar com);
//void write_date(uchar date);
//void init();
//void xianshi();
/*------------------------------------------------
mS????,?????? unsigned char t,????
unsigned char ??????????,??????
0~255 ??????12M,?????????
------------------------------------------------*/
void DelayUs2x(uchar t)
{
while(--t);
}
void DelayMs(uchar t)
{
while(t--)
{
//????1mS
DelayUs2x(245);
DelayUs2x(245);
}
}
/*------------------------------------------------
18b20???
------------------------------------------------*/
bit Init_DS18B20(void)
{
bit dat=0;
ds = 1; //DQ??
DelayUs2x(5); //????
ds = 0; //????DQ??
DelayUs2x(200); //???? ?? 480us ??960us
DelayUs2x(200);
ds = 1; //????
DelayUs2x(50); //15~60us ? ??60-240us?????
dat=ds; //??x=0??????, x=1??????
DelayUs2x(25); //??????
return dat;
}
/*------------------------------------------------
??????
------------------------------------------------*/
uchar ReadOneChar(void)
{
uchar i=0;
uchar dat = 0;
for (i=8;i>0;i--)
{
ds = 0; // ?????
dat>>=1;
ds = 1; // ?????
if(ds)
dat|=0x80;
DelayUs2x(25);
}
return(dat);
}
/*------------------------------------------------
??????
------------------------------------------------*/
void WriteOneChar(uchar dat)
{
uchar i=0;
for (i=8; i>0; i--)
{
ds = 0;
ds = dat&0x01;
DelayUs2x(25);
ds = 1;
dat>>=1;
}
DelayUs2x(25);
}
uint ReadTemperature(void)
{
uchar a=0;
uint b=0;
uint t=0;
Init_DS18B20();
WriteOneChar(0xCC); // ??????????
WriteOneChar(0x44); // ??????
DelayMs(10);
Init_DS18B20();
WriteOneChar(0xCC); //??????????
WriteOneChar(0xBE); //????????(???9????) ???????
a=ReadOneChar(); //??
b=ReadOneChar(); //??
b<<=8;
t=a+b;
return(t);
}
void write_com(uchar com)
{
rs=0;
P0=com;
DelayMs(5);
en=1;
DelayMs(5);
en=0;
DelayMs(5);
}
void write_date(uchar date)
{
rs=1;
en=0;
DelayMs(5);
P0=date;
DelayMs(5);
en=1;
DelayMs(5);
en=0;
DelayMs(5);
}
void init()
{
rw=0;
en=0;
write_com(0x38);
write_com(0x0c);
write_com(0x06);
write_com(0x01);
}
void wendu(uchar num)
{
uchar i;
uint t;
uint TempH,TempL;
uchar dis[7];
Init_DS18B20();
WriteOneChar(0x55);
if(num==1)
{
for(i=0;i<8;i++)
{
WriteOneChar(tq1[i]);
}
}
if(num==2)
{
for(i=0;i<8;i++)
{
WriteOneChar(tq2[i]);
}
}
WriteOneChar(0x44);
DelayMs(200);
Init_DS18B20();
WriteOneChar(0x55);
if(num==1)
{
for(i=0;i<8;i++)
{
WriteOneChar(tq1[i]);
}
}
if(num==2)
{
for(i=0;i<8;i++)
{
WriteOneChar(tq2[i]);
}
}
WriteOneChar(0xbe);
DelayMs(200);
t=ReadTemperature();
if(t&0x8000)
{
dis[0]=0x2d;//????
t=~t; // ???1
t +=1;
}
else
dis[0]=0x2b;
TempH=t>>4;
TempL=t&0x0F;
TempL=TempL*6/10;//??????
if(((TempH%100)/10==0))//??
dis[1]=0+0x30;
else
dis[1]=(TempH%100)/10+0x30; //????
dis[2]=(TempH%100)%10+0x30; //????,????
dis[3]=0x2e;
dis[4]=TempL+0x30;
dis[5]=0xdf;
dis[6]=0x43; //??C??
}
void main()
{
uchar i,dis[7];
Init_DS18B20();
DelayMs(2);
init();
DelayMs(2);
while(1)
{
if(num==1)
{
wendu(num);
for(i=0;i<7;i++)
{write_com(0x80+i);
write_date(dis[i]);
}
num++;
}
if(num==2)
{
wendu(num);
for(i=0;i<7;i++)
{write_com(0x80+0x40+i);
write_date(dis[i]);
}
num=1;
}
}

对吧？

我最近也在写ds18b20的程序，这个0x80是怎么回事呀

这个什么意思呀

嗯，你找个ds18b20的手册，然后里面有时序的，跟着时序写程序就可以了，嗯