city=[2101,2106,1504,1505,2201,2202,2224,1522]
station1=[12,2,3,2,5,2,1,1]
station2=[1]
print "110101~"+str(city[0])+"("+str(station2[0])+")"
print "110105~"+str(city[0])+"("+str(station1[0])+")"
print "110105~"+str(city[1])+"("+str(station1[1])+")"
print "110105~"+str(city[2])+"("+str(station1[2])+")"
print "110105~"+str(city[3])+"("+str(station1[3])+")"
print "110105~"+str(city[4])+"("+str(station1[4])+")"
print "110105~"+str(city[5])+"("+str(station1[5])+")"
print "110105~"+str(city[6])+"("+str(station1[6])+")"
print "110105~"+str(city[7])+"("+str(station1[7])+")"

简单的python代码，请自行探索
溜了溜了

# -*- coding: utf-8 -*
key1=['do','you','have','money','boom']
key2=[2,0,2,0,1,2,2,4]
key3=['G','A','M','E']
sum=key2[0]+key2[4]
print "d"+str(key2[4])+"~"+str(sum)+str(key2[1])+str(key1[4])
print "city(2101、2201、2301、2310)\n"+str(key3[0])+str(key2[0])+"**、"+str(key3[0])+str(sum)+"**\40is\40"+str(key1[4])

# -*- coding: utf-8 -*
#修订
key1=['do','you','have','money','boom']
key2=[2,0,2,0,1,2,2,4]
key3=['G','A','M','E']
sum=key2[0]+key2[4]
print "d"+str(key2[4])+"~"+str(sum)+str(key2[1])+str(key1[4])
print "city(2101、2106、2201、2202、2301、2310)\n"+str(key3[0])+str(key2[0])+"**、"+str(key3[0])+str(sum)+"**\40is\40"+str(key1[4])