我不想解题,就想把an算出来

原式化为
a(n+2) - 2 = 5(a(n+1) - 2) - 6(an - 2)
令bn = an -2
a1 = 1,b1 = -1
a2 = 5,b2 = 3
b(n+2) = 5b(n+1) - 6bn
x^2 = 5x - 6
x = 3 或者2
bn = c1*3^n +c2*2^n
b1 = 3c1 + 2c2 = -1
b2 = 9c1 + 4c2 = 3
c1 =5/3 ,c2 = -3
an = bn + 2 = 5/3*3^n - 3*2^n +2
